There is a formula about the distance between two points in the plane. M(a,b) and Т(с,d) The distance between M and N is L=sqrt[(a-c)^2+(b-d)^2)] So the magnitude of this vector is sqrt[(-6+10)^2+(-4+4)^2]=sqrt(16+0)=4 b=d This means that vector JK isparallel to the OX axis(there is a picture)
