Hello please could you answer the questions in the attachment about arc length and the area of a sector. Please show full working out.
(note I have provided 2 attachments both of the same sheet in case 1 isn't clear)
easy peasy so remember that 1 ful roation=360 degrees so if you are given an arc of x degrees, that arc's area=x/360 of total area and the arc legnth=x/360 of circumference so
1. a. 60/360 times 10 times 2 times pi=(10pi)/3 cm b. 60/360 times 10^2 times pi=(50pi)/3 cm^2
2. a. 120/360 times 5 times 2 times pi=(10pi)/3 cm b. 120/360 times 5^2 times pi=(25pi)/3 cm^2
3.a. 45/360 times 2 times 2.4 times pi=0.6pi cm b. 1/8 times 2.4^2 times pi=0.72pi cm^2
4.a. 75/360 times 3.2 times 2 times pi=(4pi)/3 cm b. (40.96pi)/3 cm^2
5.a.150/360 times 2 times 72 times pi=2pi cm b. 72pi cm^2
6.a. 15/360 times 2 times 12 times pi=pi cm b. 6pi cm^2
7.a. quarter is 1/4 so 1/4 2 pi 1.9=0.95pi cm b. 0.9025pi cm^2
Don't worry I print out your sample and do the working and give you the full solutions with another sample.......Is it an assignment by the way so I can know that you're not rushing or otherwise I can know do it fastly
