contestada

LM is the midsegment of trapezoid ABCD. AB= x + 8, LM = 4x + 3, and DC = 243. What is the value of x?

Respuesta :

According to the feature of midsegment.:
LM =(AB + DC)/2

LM = 4x + 3.
AB= x + 8.
DC = 243.

4x+3=(x+8+243)/2
8x+6=x+251
7x=245
x=35 - the answer.

Answer:

x=35

Step-by-step explanation:

Given ia a trapezoid ABCD with bases AB and CD

Mid segment is LM

AB=x+8

CD =243

LM = mid segment = average of two bases

Hence

LM = [tex]\frac{x+8+243}{2} =\frac{x+251}{2}[/tex]

Equate this to given LM value

[tex]\frac{x+251}{2} =4x+3\\x+251=8x+6\\7x=245\\x=35[/tex]

Hence answer is

x=35