Question help please these are them 3





Answer: 0
Step-by-step explanation:
[tex]log_{m} 1 = x[/tex]
1 = mˣ
1 = m⁰
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Answer: [tex]x = -\frac{2}{33}[/tex]
Step-by-step explanation:
log₁₀ (1 - 6x) = 2 restriction: 1 - 6x > 0 ⇒ x < [tex]\frac{1}{6}[/tex]
1 - 6x = 10²
1 - 6x = 100
-1 -1
-6x = 99
[tex]\frac{-6x}{-6} = \frac{99}{-6}[/tex]
x = [tex]-\frac{2}{33}[/tex]
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Answer: [tex]x = -\frac{3}{5}[/tex]
Step-by-step explanation:
[tex]\frac{1}{\sqrt[5]{27} }[/tex] = 3ˣ
[tex]\frac{1}{\sqrt[5]{3^{3}} }[/tex] = 3ˣ
[tex]\frac{1}{3^{\frac{3}{5} } }[/tex] = 3ˣ
[tex]3^{-\frac{3}{5}[/tex] = 3ˣ
[tex]-\frac{3}{5} = x[/tex]
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Answer: [tex]x = \frac{5}{9}[/tex]
Step-by-step explanation:
ln 2 + ln x = ln 5 + ln (4x - 2)
ln (2(x)) = ln (5(4x - 2))
2x = 5(4x - 2)
2x = 20x - 10
-20x -20x
-18x = -10
[tex]\frac{-18x}{-18} = \frac{-10}{-18}[/tex]
[tex]x = \frac{5}{9}[/tex]