Respuesta :

gmany

[tex]ax^2+bx+c=0\\\\x^2+7x+9=3\qquad|\text{subtract 3 from both sides}\\\\x^2+7x+9-3=3-3\\\\\boxed{x^2+7x+6=0\to A.}[/tex]

[tex]a=1,\ b=7,\ c=6[/tex]

The answer is A because you subtract 3 from both sides to get the equation set to 0