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confused on how to find the mass of player 2.

Two hockey players are traveling at velocities of v1 = 13 m/s and v2 = -17 m/s when they undergo a head-on collision. After the collision, they grab each other and slide away together with a velocity of -3.5 m/s. Hockey player 1 has a mass of 122 kg. What is the mass of the other player?

thank you.

Respuesta :

here in this type of collision we can use momentum conservation

[tex]P_{1i} + P_{2i} = P_{1f} + P_{2f}[/tex]

here we know that

[tex]m_1 = 122 kg[/tex]

[tex]v_{1i} = 13 m/s[/tex]

[tex]v_{2i} = -17 m/s[/tex]

[tex]v_{1f} = v_{2f} = - 3.5 m/s[/tex]

now by above equation of momentum conservation

[tex]122* 13 + m_2*(-17) = 122*(-3.5) + m_2*(-3.5)[/tex]

[tex]1586  - 17*m_2 = - 427 - 3.5* m_2[/tex]

[tex]1586 + 427 = (17 - 3.5)*m_2[/tex]

[tex]2013 = 13.5*m_2[/tex]

[tex]m_2 = \frac{2013}{13.5}[/tex]

[tex]m_2 = 149 kg[/tex]

so mass of the player 2 will be approx 149 kg

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