The number of hydrogen atoms that are in 7.80 moles of ammonium sulfide are 3.756 x 10^25 atoms
calculation
Step 1: calculate the moles of H in (NH4)2S
since there are 8 atoms of H in (NH4)2S the moles of
H = 8 x7.80 = 62.4 mole
Step 2: use of Avogadro's law constant to determine the number of H atom
that is 1 mole = 6.02 x10^23 atoms
62.4 moles=? atoms
= [ 62.4 x 6.02 x10^23]/ 1 mole= 3.756 x10^25 atoms
Answer: There are [tex]3.75 \times 10^{25}[/tex] number of H atoms in 7.80 mol of ammonium sulfide.
Explanation:
The formula of ammonium sulfide is [tex](NH_{4})_{2}S[/tex].
There are 2 nitrogen atoms, 8 hydrogen atoms and 1 sulfur atom in one molecule of ammonium sulfide.
Calculate moles of hydrogen atoms as follows.
[tex]8 \times 7.80[/tex] = 62.4
According to Avogadro's number 1 mole contains [tex]6.022 \times 10^{23} atoms[/tex]
Therefore, calculate number of H atoms as follows.
[tex]62.4 \times 6.022 \times 10^{23}[/tex]
= [tex]375.77 \times 10^{23}[/tex]
= [tex]3.75 \times 10^{25}[/tex]
Thus, there are [tex]3.75 \times 10^{25}[/tex] number of H atoms in 7.80 mol of ammonium sulfide.
