Respuesta :
[tex]\bf \begin{cases} -11+i\implies -11+1i\\ \qquad (-11,1)\\ -4+4i\\ \qquad (-4,4) \end{cases} \\\\\\ ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-11}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{4}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)[/tex]
[tex]\bf \left( \cfrac{-4-11}{2}~~,~~ \cfrac{4+1}{2}\right)\implies \left(-\frac{15}{2}~,~\frac{5}{2} \right)\implies \left(-7\frac{1}{2}~,~2\frac{1}{2} \right) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill -7\frac{1}{2}+2\frac{1}{2}i~\hfill[/tex]
(-11 +-4)/2 = -15/2
(i+4i)/2= 5/2 i
the midpoint is (-15/2, 5/2 i)
or (-7.5 ,2.5i)