Answer:
6.57 L
Explanation:
First, calculate the moles of hydrogen produced, then use the Ideal Gas Law to calculate the volume of hydrogen.
Step 1. Write the chemical equation.
[tex]M_{r}[/tex]: 22.99
2Na + H₂O ⟶ 2NaOH + H₂
Step 1. Convert grams of Na to moles of Na
[tex]\text{Moles of Na} = \text{15.8 g Na} \times \frac{\text{1mol Na} }{\text{22.99 g Na}}=\text{0.6873 mol Na}[/tex]
Step 2. Use the molar ratio of H₂:Na to convert moles of Na to moles of H₂.
[tex]\text{Moles of H}_{2} = \text{0.6873 mol Na} \times \frac{\text{1 mol H}_{2}}{\text{2 mol Na} } = \text{0.3436 mol H}_{2}[/tex]
Step 3. Use the Ideal Gas Law to calculate the volume of hydrogen.
pV = nRT
[tex]V = \frac{nRT }{ p}[/tex]
[tex]V = \frac{\text{0.3436 mol} \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1}\times \text{303 K}}{\text{1.30 atm}} = \textbf{6.57 L}[/tex]
