Respuesta :
vector A has magnitude 12 m and direction +y
so we can say
[tex]\vec A = 12 \hat j[/tex]
vector B has magnitude 33 m and direction - x
[tex]\vec B = -33 \hat i[/tex]
Now the resultant of vector A and B is given as
[tex]\vec A + \vec B = 12 \hat j - 33 \hat i[/tex]
now for direction of the two vectors resultant will be given as
[tex]\theta = tan^{-1}\frac{12}{-33}[/tex]
[tex]\theta = 160 degree[/tex]
so it is inclined at 160 degree counterclockwise from + x axis
magnitude of A and B will be
[tex]R = \sqrt{A^2 + B^2}[/tex]
[tex]R = \sqrt{12^2 + 33^2} = 35.11 m[/tex]
so magnitude will be 35.11 m
