The number of calories that are required to do so is 1 .2 x10^8 cal
calculation
where M=mass in grams ( gotten by converting L into g)
where 1 L = 1000 g
6000L=? g
by cross multiplication
= [6000 x1000] =6,000,000 g
- C = specific heat capacity for water= 1 cal/g/c
- ΔT=change in temperature = 20c-0c= 20 c
therefore heat = 6,000,000 g x 1 cal/g/c x 20 c= 1.2 x10^8 cal
