Respuesta :

parkerfreeze

x would be equal to or less than 4. It would not be possible for it to have a length of 15 because 15x10=150 and the maximum area is 140 sq cm.

Answer:

Step-by-step explanation:

Part A:

The length is given as = [tex]3x+2[/tex] cm

The width is give as = 10 cm

Area of rectangle = length x width

Area = [tex](3x+2)10[/tex]

Given is that the area of the rectangle shown is at most of 140 square cm.

So, we can write this as:

[tex](3x+2)10 \leq140[/tex]

Solving this we get;

[tex]30x+20 \leq140[/tex]

=> [tex]30x \leq140-20[/tex]

=> [tex]30x \leq120[/tex]

We get [tex]x \leq4[/tex]

So, [tex]3(4)+2[/tex] = 14 cm

Hence, the length can be 14 cm and width is 10 cm.

Part B:

No, it is not possible as if the length will be 15, it will give an area of 150 cm square that is greater than 140 cm square.

Otras preguntas