Respuesta :
Answer:[tex]1.1683\times 10^{13}[/tex] number of photons.
Explanation:
[tex]\text{Energy of photon}=E= \frac{hc}{\lambda }[/tex]
[tex]E= \frac{6.626\times 10^{-34}J s\times 3\times 10^{8}m/s}{860\times 10{-9}m}=0.02311\times 10^{-17} J [/tex]
[tex]\text{Energy of radiation}=2.7\mu J=2.7\times 10^{-6}J(1\mu J=10^{-6}J)[/tex]
[tex]\text{Energy of radiation}=E\times \text{Number of photons}[/tex]
[tex]\text{Number of photons}=\frac{\text{Energy of radiation}}{\text{Energy of photon}(E)}=\frac{2.7\times 10^{-6}J}{0.02311\times 10^{-17} J}=1.1683\times 10^{13}\text{photons}[/tex]
[tex]1.1683\times 10^{13}[/tex] numbers of photons will be contained by [tex]2.7\mu J[/tex] pulse of monochromatic radiation.
