Respuesta :
Answer: Empirical formula is [tex]C_2H_5O[/tex]
Explanation: We are given the masses of elements present in a sample of compound. To evaluate empirical formula, we will be following some steps.
Step 1 : Converting each of the given masses into their moles by dividing them by Molar masses.
[tex]Moles=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Molar mass of Carbon = 12.0 g/mol
Molar mass of Hydrogen = 1.0 g/mol
Molar mass of Oxygen = 16.0 g/mol
Moles of Carbon = [tex]\frac{330g}{12g/mol}=27.5moles[/tex]
Moles of Hydrogen = [tex]\frac{69.5g}{1g/mol}=69.5moles[/tex]
Moles of Oxygen = [tex]\frac{220.2g}{16g/mol}=13.76moles[/tex]
Step 2: Dividing each mole value by the smallest number of moles calculated above and rounding it off to the nearest whole number value
Smallest number of moles = 13.76 moles
[tex]\text{Mole ratio of Carbon}=\frac{27.5moles}{13.76moles}=1.99\approx 2[/tex]
[tex]\text{Mole ratio of Hydrogen}=\frac{69.5moles}{13.76moles}=5.05\approx 5[/tex]
[tex]\text{Mole ratio of Oxygen}=\frac{13.76moles}{13.76moles}=1[/tex]
Step 3: Now, the moles ratio of the elements are represented by the subscripts in the empirical formula
Empirical formula becomes = [tex]C_2H_5O[/tex]
