Answer:
Step-by-step explanation:
let X be the random variable for number of times the clock fails .
X is Poisson with average = 6.8% = 0.0068
PDF of x = e^(-0.0068) 0.0068^x/x!
a) The probability that the student's alarm clock will not work on the morning of an important final exam = P(X=0) = 0.00675
b) If the student has two such alarm clocks, the probability that they both fail on the morning of an important final exam:
Since both clocks are independent prob for both failing is
P(x1 fails) *P(x2 fails) = 0.00675(0.00675) = 0.000455625
c) the probability of not being awakened if the student uses three independent alarm clocks = Prob for all 3 fails = 0.00675^3
= 0.00000307546
d) Yes. Because all three fail probability is almost zero.
D. Yes, because you can always be certain that at least one alarm clock will work.