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How many milliliters of a 0.266 M RbNO3 solution are required to make 150.0 mL of 0.075 M RbNO3 solution? How many milliliters of a 0.266 M RbNO3 solution are required to make 150.0 mL of 0.075 M RbNO3 solution? 42.3 mL 53.2 mL 35.1 mL 18.8 mL 23.6 mL

Respuesta :

Answer : 42.3 ml of a 0.266 M [tex]RbNO_3[/tex] solution are required.

Solution : Given,

Molarity of [tex]RbNO_3[/tex] solution 1 = 0.266 M

Molarity of [tex]RbNO_3[/tex] solution 2 = 0.075 M

Volume of [tex]RbNO_3[/tex] solution 2 = 150 ml = 0.150 L      (1 L = 1000 ml)

Formula used :

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1[/tex] = Molarity of [tex]RbNO_3[/tex] solution 1

[tex]M_2[/tex] = Molarity of [tex]RbNO_3[/tex] solution 2

[tex]V_1[/tex] = Volume of [tex]RbNO_3[/tex] solution 1  

[tex]V_2[/tex] = Volume of [tex]RbNO_3[/tex] solution 2

Now put all the given values in above formula, we get

[tex]0.266M\times V_1=0.075M\times 0.150L\\V_1=0.042293L=42.293ml\approx 42.3 ml[/tex]                 (1 L = 1000 ml)

Therefore, 42.3 ml of a 0.266 M [tex]RbNO_3[/tex] solution are required.

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