X = -11.
11(x+10)+5x=11+7x
11x + 110 + 5x = 11 + 7x
(11x + 5x) + 110 = 7x + 11.
16x + 110 = 7x + 11.
16x + 110 - 7x = 7x + 11 - 7x
9x + 110 + 11.
9x + 110 - 110 =11 - 110.
9x/9 = -99/9
X = -11
How to get answer by Mimiwhatsup:
[tex]11\left(x+10\right)+5x=11+7x\\11\left(x+10\right)+5x\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=11,\:b=x,\:c=10\\a=11,\:b=x,\:c=10\\\mathrm{Multiply\:the\:numbers:}\:11\cdot \:10=110\\=11x+110\\=11x+110+5x\\11x+110+5x\\Group\:like\:terms\\=11x+5x+110\\\mathrm{Add\:similar\:elements:}\:11x+5x=16x\\=16x+110\\16x+110=11+7x\\\mathrm{Subtract\:}110\mathrm{\:from\:both\:sides}\\16x+110-110=11+7x-110\\Simplify\\16x=7x-99\\[/tex]
[tex]\mathrm{Subtract\:}7x\mathrm{\:from\:both\:sides}\\16x-7x=7x-99-7x\\\mathrm{Simplify}\\9x=-99\\\mathrm{Divide\:both\:sides\:by\:}9\\\frac{9x}{9}=\frac{-99}{9}\\Simplify\\\frac{9x}{9}=x\\\frac{9x}{9}\\\mathrm{Divide\:the\:numbers:}\:\frac{9}{9}=1\\=x\\\frac{-99}{9}=-11\\\frac{-99}{9}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}\\=-\frac{99}{9}\\\mathrm{Divide\:the\:numbers:}\:\frac{99}{9}=11\\\\Answer: -11[/tex]
