A diver descends to a location of -50 1 over 4 meters relative to the surface of the water. He then descends another 10 1 over 2 meters. What is the diver's final location relative to the surface of the water? Enter your answer as a simplified mixed number in the box

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Answer:

[tex]-60\frac{3}{4}[/tex] meters.

Step-by-step explanation:

To find diver's final location relative to the surface of water we will subtract  [tex]10\frac{1}{2}[/tex] from [tex]-50\frac{1}{4}[/tex] because diver dives away another [tex]10\frac{1}{2}[/tex] from his previous location of [tex]-50\frac{1}{4}[/tex].

[tex]-50\frac{1}{4} -10\frac{1}{2}[/tex]

Now we will convert our mixed fraction into improper fraction and then we will find a common denominator.

[tex]\frac{-201}{4} -\frac{21}{2} =\frac{-201-42}{4}[/tex]

[tex]=\frac{-243}{4}[/tex]

Now let us convert our answer in mixed fraction.

[tex]=\frac{-243}{4}=[tex]-60\frac{3}{4}[/tex][/tex]

Therefore, diver's final location relative to the surface of the water is [tex]-60\frac{3}{4}[/tex] meters.

Answer:

The correct answer is -60  3/4

Step-by-step explanation:

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