Answer : Y > W > X > Z
Explanation :
The electrostatic force is given by :
[tex]F=k\dfrac{q_1q_2}{d^2}[/tex]
k is the electrostatic constant
q₁ and q₂ are charges
d is the distance between them
We will calculate forces one by one :
[tex]F=k\dfrac{q.q}{d^2}=\dfrac{kq^2}{d^2}[/tex]
[tex]W=k\dfrac{q.2q}{d^2}=\dfrac{2kq^2}{d^2}=2F[/tex]
[tex]X=k\dfrac{q.q}{(2d)^2}=\dfrac{kq^2}{4d^2}=\dfrac{F}{4}[/tex]
[tex]Y=k\dfrac{3q.q}{d^2}=\dfrac{3kq^2}{d^2}=3F[/tex]
[tex]Z=k\dfrac{q.q}{(3d)^2}=\dfrac{kq^2}{9d^2}=\dfrac{F}{9}[/tex]
So, the force from greatest to least will be :
Y > W > X > Z
So, the correct option is (B)
