Answer:
Quadratic: y=x^2-27x-160
not too sure of the other ones sorry
Step-by-step explanation:
The equations are- 1) y=-6x+2, 2) y = x^2+7, 3) y = -1/5x^3+7
Step-Wise explanation-
Linear function
let y = -6x+2
if we put x=5 then- y = 32
quadratic function
let y = x^2+7
if we put x=5 then we get y = 32
Cubic function
let y = -1/5x^3+7
if we again put x=5 then we get y= 32
Hence the required functions are y = -6x+2, y = x^2+7, y = -1/5x^3+7
the function is the relationship between units of values. e g y=f(x), for each value of x there is its exists in a set of y. x is an impartial variable even as Y depends variable.
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