slope = - [tex]\frac{2}{3}[/tex]
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
rearrange 2x + 3y = - 12 into this form
subtract 2x from both sides
3y = - 2x - 12 ( divide all terms by 3 )
y = - [tex]\frac{2}{3}[/tex] x - 4 ← in slope- intercept form
with slope m = - [tex]\frac{2}{3}[/tex]
[tex]\text{The slope-intercept form:}\ y=mx+b\\m-slope,\ b-y-intercept\\\\2x+3y=-12\qquad|\text{subtract 2x from both sides}\\\\3y=-2x-12\qquad|\text{divide both sides by 3}\\\\y=-\dfrac{2}{3}x-4\\\\Answer:\ \boxed{m=-\dfrac{2}{3}}[/tex]
