Answer:
Resistor R₃ = 10 Ω
Explanation:
It is given that,
Current flowing in the circuit, I = 2 A
Resistors R₁ = 2 Ω
Resistor R₂ = 3 Ω
Voltage, V = 30 V
We have to find the value of R₃. All three resistors are connected in series. In series combination, the current flowing through the all resistors is same. Firstly, calculating equivalent resistance of three resistors as :
[tex]R_{eq}=R_1+R_2+R_3[/tex]
[tex]R_{eq}=2\ \Omega+3\ \Omega+R_3[/tex]
[tex]R_{eq}=5\ \Omega+R_3[/tex]..............(1)
Using Ohm's law : [tex]V=IR_{eq}[/tex]
[tex]30\ V=2\ A\times (5 + R_{3})[/tex]
On solving above equation : [tex]R_3=10\ \Omega[/tex]
Hence, the correct option is (A) " 10 Ω "
