2 Suppose that a new element (E) were discovered that existed as three natural isotopes: 25% of atoms had a mass of 278, 38% had a mass of 281, and the remained had a mass of 285. What would be listed as the atomic mass of this element? Explain your logic and show all steps.

Respuesta :

Answer: Atomic mass of the element E is 281.73 amu.

Explanation: We are given an element E, having 3 isotopes.

Atomic mass of the element is calculated by:

[tex]\text{Atomic mass of the element}=\sum_{i=1}^n(\text{Mass of isotope})_i(\text{Fractional abundance})_i[/tex] .....(1)

Fractional abundance can be calculated by:

[tex]\text{Fractional abundance}=\frac{\text{Percentage abundance}}{100}[/tex]

Mass of isotope 1 = 278 amu

Fractional abundance of isotope 1 =[tex]\frac{25}{100}[/tex] =0.25

Mass of isotope 2 = 281 amu

Fractional abundance of isotope 2 = 0.38

Mass of isotope 3 = 285 amu

Total fractional abundance = 1

Fractional abundance of isotope 3 = 1 - (0.25+0.38) = 0.37

Putting all the values in equation 1, we get

[tex]\text{Atomic mass of the element}=\left[(278\times 0.25)+(281\times 0.38)+(285\times 0.37) \right ][/tex]

Atomic mass of the element E = 281.73 amu.