Answer:
11.19 %
Explanation:
1 molecule water = 2 H + 1 O
If H = 1.008 u and O = 16.00 u, then
Water = 2H + 1 O = (2 × 1.008 u) + (1 × 16.00 u) = 2.016 u + 16.00 u = 18.02 u
The formula for mass percent is
[tex]\% \text{ by mass} = \frac{\text{Mass of H}}{\text{Total mass}} \times 100 \%[/tex]
So,
[tex]\%\text{ H} = \frac{\text{2.016 u}}{\text{18.02 u}} \times 100 \% = 11.19 \%[/tex]
