Answer:
a) 2.7 mol
Explanation.:
2Al + 3Cl₂ ⟶ 2AlCl₃
We want to convert moles of Cl₂ to moles of AlCl₃.
Choose the conversion factor ( the correct molar ratio)
It is or either [tex]\frac{\text{3 mol Cl}_{2}}{\text{2 mol AlCl}_{3}}[/tex] or [tex]\frac{\text{2 mol AlCl}_{3}}{\text{3 mol Cl}_{2}}[/tex]
We choose the one with the desired units (mol AlCl₃) on top.
[tex]\text{Moles of AlCl}_{3} = \text{4.0 mol Cl}_{2} \times \frac{\text{2 mol AlCl}_{3}}{\text{3 mol Cl}_{2}} = \text{2.7 mol AlCl}_{3}[/tex]