katmarie123
contestada

A 250.0 mL sample of air at 100.0 K is warmed to 200.0 k at constant pressure .What is the volume of the air sample at the new temperature? Show your work below.

Respuesta :

znk

Answer:

500.0 mL

Explanation:

From Charles’ Law, we know that

[tex]\frac{V_{1} }{T_{1} }= \frac{V_{2} }{T_{2 }}[/tex]

We can solve this equation to get

[tex]V_{2} = V_{1} \times \frac{ T_{2}}{ T_{1}}[/tex]

[tex]V_{2} = \text{250.0 mL} \times \frac{\text{200.0 K}}{\text{100.0 K}} = \textbf{500.0 mL}[/tex]

onyebuchinnaji

The new volume of the air sample at the given new absolute temperature is 500 L.

The given parameters;

  • volume of the air sample, v = 250 mL
  • initial temperature of the air sample, T₁ = 100 K
  • final temperature of the air sample, T₂ = 200 K

The new volume of the air sample at the given new absolute temperature is determined using Charles' law as shown below;

[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2} \\\\V_2 = \frac{V_1 T_2}{T_1} \\\\V_2 = \frac{(250 mL) \times 200}{100}\\\\V_2 = 500 \ mL[/tex]

Thus, the new volume of the air sample at the given new absolute temperature is 500 L.

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