This question involves the concept of Coulomb's Law and electrostatic force.
When distance between two charges is increased to three times the original distance, then the electrical force between the charges will compare with the original force in a way that "D) It will decrease to one-ninth the original force.".
What is Coulomb's Law?
According to Coulomb's Law, the magnitude of the electrostatic force between the charges is given by the following formula:
[tex]F =\frac{kq_1q_2}{r^2}[/tex]
where,
- F = electrostatic force
- k = coulomb's constant
- q₁ = magnitude of first charge
- q₂ = magnitude of second charge
- r = distance between charges
Now, if increase the distance between the charges to three times the original distance, then the force will become:
[tex]F'=\frac{kq_1q_2}{(3r)^2}\\\\F'=\frac{1}{9}\frac{kq_1q_2}{r^2}\\\\F'=\frac{1}{9}F[/tex]
Hence, the force will be reduced to one-ninth the original force.
Learn more about Coulomb's Law here:
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