9. An irregularly-shaped sample of aluminum (Al) is put on a balance and found to have a mass of 43.6 g. The student decides to use the water-displacement method to find the volume. The initial volume reading is 25.5 mL and, after the Al sample is added, the water level has risen to 41.7 mL. Find the density of the Al sample in g/cm3. (Remember: 1 mL = 1 cm3.)

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The density is 2.69 g/ml

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The density of the irregularly shaped Aluminum block has been 2.69 g/ml.

The water displacement method is used for the determination of the volume of the object.

The volume displaced has been equivalent to the volume of the object that displaces water.

The volume of object = Final volume - Initial method

The volume of the object = 41.7 ml - 25.5 ml

The volume of the object = 162 ml

The density can be expressed as the mass per unit volume. The density can be given as:

Density = [tex]\rm \dfrac{Mass}{Volume}[/tex]

The density of the Al has been:

Density = [tex]\rm \dfrac{43.6}{16.2}[/tex]

Density = 2.69 g/ml.

The density of the irregularly shaped Aluminum block has been 2.69 g/ml.

For more information about the water displacement method, refer to the link:

https://brainly.com/question/18166350