Answer:- [tex]HCO_3^-(aq)+HS^-(aq)\rightleftharpoons CO_3^2^-(aq)+H_2S(aq)[/tex]
Explanations:- As per Bronsted-Lowry acid-base concept, acids are proton(hydrogen ion) donors and bases are proton acceptors.
Since the bicarbonate ion is acting as an acid, it would donate proton to the bisulfide. The products are carbonate ion and hydrosulfuric acid.
The equation is written as:
[tex]HCO_3^-(aq)+HS^-(aq)\rightleftharpoons CO_3^2^-(aq)+H_2S(aq)[/tex]
[tex]HCO_3^-[/tex] is bicarbonate ion
[tex]HS^-[/tex] is bisulfide ion
[tex]CO_3^2^-[/tex] is carbonate ion and
[tex]H_2S[/tex] is hydrosulfuric acid.
