Let's assume
the number of bags of candy =x
the number of bags of cookies =y
There were 5 more bags of cookies sold than candy
so, we get
[tex]y=x+5[/tex]
Bags of candy cost $5.50
so, total cost of candy is
[tex]=5.50x[/tex]
bags of cookies cost $3.50
so, total cost of cookies is
[tex]=3.50y[/tex]
so,
total cost = (total cost of candy)+(total cost of cookies)
we get
total cost =5.50x+3.50y
so, we can plug
[tex]5.50x+3.50y=53.50[/tex]
now, we can plug y
[tex]5.50x+3.50(x+5)=53.50[/tex]
[tex]5.5x\cdot \:10+3.5\left(x+5\right)\cdot \:10=53.5\cdot \:10[/tex]
[tex]55x+35\left(x+5\right)=535[/tex]
[tex]55x+35x+175=535[/tex]
[tex]90x+175=535[/tex]
[tex]90x+175-175=535-175[/tex]
[tex]90x=360[/tex]
[tex]x=4[/tex]
now, we can find y
[tex]y=x+5[/tex]
[tex]y=4+5[/tex]
[tex]y=9[/tex]
so,
the number of bags of candy =4
the number of bags of cookies =9............Answer
