Respuesta :
The pojnt-slope form of a line:
[tex]y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (-4, 1) and (2, 1).
Substitute:
[tex]m=\dfrac{1-1}{2-(-4)}=\dfrac{0}{6}=0\\\\y-1=0(x-(-4))\\\\y-1=0\to y=1[/tex]
The pojnt-slope form of a line:
[tex]y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (-4, 1) and (2, 1).
Substitute:
[tex]m=\dfrac{1-1}{2-(-4)}=\dfrac{0}{6}=0\\\\y-1=0(x-(-4))\\\\y-1=0\to y=1[/tex]