Respuesta :

klocke2001

(4.20 mol O) x (1 mol H2SO4 / 4 mol O) = 1.05 mol H2SO4 (4.20 mol O) x (1 mol C2H4O2 / 2 mol O) = 2.10 mol C2H4O2 (4.20 mol O) x (1 mol NaOH / 1 mol O) = 4.20 mol NaOH

Cricetus

The compounds are present will be "1.325 of H₂SO₄, 2.65 of C₂H₄O₂, 5.30 of NaOH". A complete solution is provided below.

Given:

  • Moles of O = 5.30 mole

As we know,

→ [tex]Any \ element \ moles \ in \ compound = Number \ of \ elements\times Moles \ of \ compound[/tex]

or,

→ [tex]Moles \ of \ compound = \frac{Any \ element \ moles \ in \ compound}{Number \ of \ elements}[/tex]

→ H₂SO₄ moles will be:

= [tex]\frac{Moles \ of \ O}{4}[/tex]

= [tex]\frac{5.30}{4}[/tex]

= [tex]1.325[/tex]

→ C₂H₄O₂ moles will be:

= [tex]\frac{Moles \ of \ O}{2}[/tex]

= [tex]\frac{5.30}{2}[/tex]

= [tex]2.65[/tex]

→ NaOH moles will be:

= [tex]Moles \ of \ O[/tex]

= [tex]5.30[/tex]

Learn more:

https://brainly.com/question/8783665