Answer: P(made 2nd attempt|made 1st attempt)=P(made 1st attempt and made 2nd attempt)P(made 1st attempt)
Step-by-step explanation:
A basketball player that shoots 80% from the free throw line attempts two free throws.
Let Event A be made 1st attempt by basket player and Event B be made 2nd attempt by basket player. These events are dependent or not independent.
A dependent event is when one event impact the outcome of another event in a situation of probability .
Here A is given event which already occurred (made 1st attempt) and probability of getting B (made 2nd attempt) after Event A is given by
The conditional probability of Event B given Event A is P(B|A)=P(A and B)/P(A) or P(made 2nd attempt|made 1st attempt)=P(made 1st attempt and made 2nd attempt)P(made 1st attempt) .
Answer:
Option 3
Step-by-step explanation:
Let A and B be two dependent events, then the probability of A given that B occurred is: P (A | B) = P (B and A) / P (B)
This means, that if event B occurred, then, the probability of occurrence A, is equal to the probability of occurrence B and A, between the probability of B
Entocnes, for this case the correct notation is:
P (made 2nd attempt | made 1st attempt) = P (made 1st attempt and made 2nd attempt) /P (made 1st attempt)
So the correct answer for this question is the third option
