Answer:
Only one solution
Step-by-step explanation:
Given that there is a coordinate plane (say xy)
Two lines are given.
One line crosses the y axis at 3 and has a slope of negative 1.
hence equation of I line is y = -x+3
The other line crosses the y axis at 3 and has a slope of two thirds.
So equation is y = 2x/3 +3
Since the two lines lie in the same plane and are having different slopes, they intersect at one point.
Eliminate y to get
-x+3=2x/3+3
Or x=0
y=3
Hence solutionis (0,3) for the system.
Answer:
One solution
Step-by-step explanation:
we know that
The solution of the system of equations is equal to the intersection point both graphs
we have
[tex]y=-x+3[/tex] ------> equation A
[tex]y=-(2/3)x+3[/tex] ------> equation B
Using a graphing tool
see the attached figure to better understand the problem
In this problem the intersection point is only one
therefore
The system of equations has one solution
The solution is the point [tex](0,3)[/tex]
