Respuesta :
Answer:
[tex]4.1975\cdot 10^{7}[/tex]
Step-by-step explanation:
We are told that the average human heart beats [tex]1.15\cdot 10^{5}[/tex] times per day and there are [tex]3.65\cdot 10^{2}[/tex] days in one year.
To find number of heart beats in one year we will multiply number of heart beats in one day by number of days in one year.
[tex]1.15\cdot 10^{5}\times 3.65\cdot 10^{2}[/tex]
Now we will solve this problem using exponent properties.
[tex]1.15 \times 3.65\cdot 10^{2+5}[/tex]
[tex]1.15 \times 3.65\cdot 10^{7}[/tex]
[tex]4.1975\cdot 10^{7}[/tex]
Our answer is in scientific notation we can represent it in standard form as [tex]4.1975\cdot 10^{7}=4.1975*10000000=41975000[/tex] times.
Therefore, average human heart beats in one year [tex]4.1975\cdot 10^{7}[/tex] or 41975000 times.
