Use the three steps to solve the problem. Two planes leave an airport at noon. If the eastbound plane flies at 560 mph and the westbound plane flies at 500 mph, at what time will they be 2,000 miles apart? Round your answer to the nearest minute.

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musiclover10045 musiclover10045 · Answer 1 · 2018-10-23T14:26:35+02:00

The distance formula is: Distance = Rate x Time.

We know the distance: 2000 miles.

We know the rates: 560 and 500 mph.

We need to solve for time:

2000 = (560 + 500) * T

2000 = 1060 *T

T = 2000 / 1060

T = 1.89 hours ( 1 hour 53 minutes)

They left at noon:

12:00 pm + 1 hour and 53 minutes = 1:53 pm.

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kobenhavn kobenhavn · Answer 2 · 2021-10-05T13:22:24+02:00

The two planes are [tex]2000[/tex] miles apart at [tex]1:53[/tex] p.m.

Distance [tex]= 2000[/tex] miles

When both are traveling in opposite directions, speeds are added.

So, net speed [tex]= (560+500) = 1060[/tex] mph.

[tex]Speed = \frac{Distance}{Time}[/tex]

[tex]Time = \frac{Distance}{Speed}[/tex]

[tex]Time = \frac{2000}{1060}[/tex]

[tex]Time = 1.89[/tex] hour

or

Time [tex]= 1[/tex] hour [tex]53[/tex] minutes.

They leave at noon:

[tex]12:00[/tex] p.m [tex]+ 1[/tex] hour [tex]53[/tex] minutes [tex]= 1:53[/tex] p.m

So, the two planes are [tex]2000[/tex] miles apart at [tex]1:53[/tex] p.m.

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