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A circuit carries a current of 0.64 A when there is a resistance of 50.0 Ω.

The voltage applied to the circuit, to the nearest whole number, is ____V.

Respuesta :

Ammimochi

The equation that relates: voltage (V), current (I) and resistance (R) is V = IR.

In this case  I = 0.64 Amps and R = 50 Ohms. Thus the voltage is simply 0.64 multiplied by 50 and the answer is: 32 Volts.

rahulsharma789888

A circuit carries a current of 0.64 A when there is a resistance of 50.0 Ω.

The voltage applied to the circuit, to the nearest whole number, is 32V.

What is resistance?

Resistance is the obstruction of electrons in an electrically conducting material. The SI unit of the resistance is Ohm

The mathematical relation for resistance can be understood with the help of the empirical relation provided by Ohm's law.

V=IR

where V is the voltage

I is the current

R is the resistance

For calculating equivalent resistance in series combination.

Re = R1  + R2

For the given problem when a circuit carries a current of 0.64 A and there is a resistance of 50.0 Ω. by using ohms law

V=IR

By substituting the values of resistance and current

V=-0.64 ×50.0

V=32

The voltage applied to the circuit, to the nearest whole number is 32V.

Learn more about resistance from here given link

brainly.com/question/14547003

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