A point charge of 4.0 µC is placed at a distance of 0.10 m from a hard rubber rod with an electric field of 1.0 × 103 . What is the electric potential energy of the point charge?

× 10–4 J

What is the electric potential energy of the point charge at 1.3 m?

× 10–3 J

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Ammimochi Ammimochi · Answer 1 · 2018-10-23T19:38:47+02:00

The electric potential energy of the point charge is 4.

the electric potential energy of the point charge at 1.3 m is 5.2.

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aristocles aristocles · Answer 2 · 2019-07-20T03:59:05+02:00

Answer:

Part 1)

[tex]U = 4 \times 10^{-4} J[/tex]

Part 2)

[tex]U = 5.2 \times 10^{-3} J[/tex]

Explanation:

Electric field due to rubber rod is given by

[tex]E = 1.0 \times 10^3 N/c[/tex]

now we also know that

[tex]V = E. r[/tex]

[tex]V = (1.0 \times 10^3)(0.10)[/tex]

[tex]V = 1.0 \times 10^2[/tex]

now potential energy is given as

[tex]U = qV[/tex]

[tex]U = (4 \mu C)(1.0 \times 10^2)[/tex]

[tex]U = 4 \times 10^{-4} J[/tex]

Similarly the electric potential at distance r = 1.3 m

so we have

[tex]V = (1.0 \times 10^3)(1.3)[/tex]

[tex]V = 1.3 \times 10^3 Volts[/tex]

now potential energy is given as

[tex]U = (4\mu C)(1.3 \times 10^3)[/tex]

[tex]U = 5.2 \times 10^{-3} J[/tex]