Answer:
the graph on the right-top
Step-by-step explanation:
Transferring an "x" to the right side in [tex]x+y\ge-3[/tex], we get [tex]y\ge -x-3[/tex]
The system of inequalities is
[tex]\left \{ {{y<2x+2} \atop {y\ge -x-3}} \right.[/tex]
We have y=2x+2 - ascending function with a=2, b=2
b=2 shows that ascending function intersects Y-axis is in y=2 - that situation is only on the right-top and left-down. So, we refuse left-top and right-down.
y=-x-3 - descending function with a=-1, b=-3
y<2x+2 is an area below the ascending function and we see that on the left-
[tex]y\ge-x-3[/tex] is an area above the descending function
On the left-down we have an area above both functions, so we refuse this picture
Right-top is correct
