Answer:
335 000 g
Explanation:
We know that we will need a chemical equation with masses and molar masses, so let’s start by gathering all the information in one place.
[tex]M_{r}[/tex]: 2.016 32.04
CO + 2H₂ ⟶ CH₃OH
Mass/kg: 42.2
1. Use the molar mass of H₂ to calculate the moles of H₂.
Note: 1 g/mol ≡ 1 kg/kmol
[tex]\text{Moles of H}_{2} = \text{42.2 kg}\times \frac{\text{1 kmol} }{\text{2.016 kg}}= \text{20.93 kmol}[/tex]
2. Use the molar ratio of CH₃OH:H₂ to calculate the moles of CH₃OH.
[tex]\text{Moles of CH$_{3}$OH} = \text{20.93 kmol H}_{2} \times \frac{\text{1 kmol CH$_{3}$OH}}{\text{2 kmol H}_{2}} = \text{10.47 kmol CH$_{3}$OH}[/tex]
3.Use the molar mass of CH₃OH to calculate the mass of CH₃OH.
[tex]\text{Mass of CH$_{3}$OH} = \text{10.47 kmol CH$_{3}$OH}\times \frac{\text{32.04 kg CH$_{3}$OH} }{\text{1 kmol CH$_{3}$OH }}= \text{335 kg CH$_{3}$OH}[/tex]
[tex]= \text{335 000 g CH$_{3}$OH}[/tex]
