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  • 24-10-2018
  • Mathematics
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Solve t^2a=t^2e−r for t
[tex]t^{2}a=t^{2}e-r[/tex]

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jdoe0001 jdoe0001
  • 24-10-2018

[tex]\bf t^2a=t^2e-r\implies t^2a-t^2e=-r\implies t^2(a-e)=-r \\\\\\ t^2=\cfrac{-r}{a-e}\implies t=\pm\sqrt{\cfrac{-4}{a-e}}[/tex]

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