Respuesta :
Answer : The atomic number and nucleon of the isotope formed in 1st step i.e X are 107 and 264.
The atomic number and nucleon of the isotope formed in 2nd step i.e Y are 105 and 260.
Explanation :
Given : Element = Meitnerium
Atomic number = 109
Atomic mass = 268
Alpha decay : It is a radioactive decay in which nucleus emits an alpha particle and turns into different atomic nucleus. During alpha decay, an atom loses 2 protons and 2 neutrons.
Step 1 : Alpha decay equation when Meitnerium undergoes alpha decay.
[tex]^{268}_{109}Mt\rightarrow ^{264}_{107}X+^4_2\alpha [/tex]
Step 2 : Alpha decay equation when [tex]^{264}_{107}X[/tex] undergoes alpha decay.
[tex]^{264}_{107}X\rightarrow ^{260}_{105}Y+^4_2\alpha [/tex]
Nucleon number : It is also known as atomic mass number and it is equal to the total number of protons & neutrons in the nucleus of an atom.
Nucleon number = Atomic mass number
Therefore, The atomic number and nucleon of the isotope formed in 1st step i.e X are 107 and 264.
The atomic number and nucleon of the isotope formed in 2nd step i.e Y are 105 and 260.
