F = applied force on the wheelbarrow in forward direction = 600 N
f = frictional force pushing in backward direction of wheelbarrow = ?
m = mass of the wheelbarrow = 28 kg
Since wheelbarrow moves forward at a constant velocity
a = acceleration of the wheelbarrow in forward direction = 0 m/s²
force equation for the motion of wheelbarrow in forward direction is given as
F - f = ma
inserting the above values in the formula
600 - f = (28) (0)
600 - f = 0
f = 600 N
hence the frictional force comes out to be 600 N
