the price of a train ticket consists of an initial fee plus a constant fee per stop. the table compares the number of stops and the price of a ticket(in dollars) plz help

We can express the question using an algebraic expression. This algebraic expression would be having two variables, x and y.
We are told in the question that:
The price of a train ticket consists of an initial fee plus a constant fee per stop.
Where:
x = Initial fee
y = Constant fee per stop
For 3 stops, our algebraic expression is given as:
x + 3y = 6.50...........Equation 1
To find the fee per stop, we compare with the algebraic expression for 7 stops
For 7 stops, our algebraic expression is given as:
x + 7y = 12.50...............Equation 2
We solve for y(constant fee per stop) using the Elimination Method.
We eliminate x by subtracting Equation 1 from Equation 2
x + 3y = 6.50...........Equation 1
x + 7y = 12.50..........Equation 2
7y - 3y = 12.50 - 6.50
4y = 6.00
Divide both sides by the coefficient of y = 4
4y/4 = 6.00/4
y = 1.50.
Therefore, the fee per stop is $1.50
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