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A gas is heated from 263 K to 298 K, and the volume is increased from 24 L to 35 L. If the original pressure is 1 atm, what would the final pressure be? *

Respuesta :

Since for closed system moles of the gas is always conserved

so as per idea gas equation we can say

[tex]n = \frac{PV}{RT}[/tex]

so here we can say

[tex]n_1 = n_2[/tex]

so here we have

[tex]\frac{P_1V_1}{RT_1} = \frac{P_2V_2}{RT_2}[/tex]

as we know that

[tex]T_1 = 263 K[/tex]

[tex]T_2 = 298 K[/tex]

[tex]V_1 = 24 L[/tex]

[tex]V_2 = 35 L[/tex]

[tex]P_1 = 1 atm[/tex]

now from above equation

[tex]\frac{1*24}{263} = \frac{P*35}{298}[/tex]

on solving above equation we have

[tex]P = 0.78 atm[/tex]

so here pressure will be 0.78 atm

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