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The half life of carbon is 5,730 years. What fraction of the original 14/6 C would be in a wooden axe handle that was 17,190 years old? (Plz explain how u got it step by step if u can T^T)

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Answer:

[tex]\frac{1}{8}[/tex]  

Explanation:

The half-life of carbon (5730 y) is the time it takes for half the carbon to decay.

After one half-life, half (50 %) of the original amount will remain.

After a second half-life, half of that amount (25 %) will remain, and so on.

[tex]\text{17 190 y} \times \frac {\text {1 half-life}}{\text{5730 y}} = \text{3 half-lives}[/tex]  

We can construct a table.

No of half-lives  Fraction remaining

            1                       [tex]\frac{1}{2}[/tex]  

            2                      [tex]\frac{1}{4}[/tex]  

            3                      [tex]\frac{1}{8}[/tex]  

The general formula is

[tex]\text{Fraction remaining} = \frac{1}{2^{n}}[/tex]

where n = the number of half-lives.

Thus, [tex]\frac{1}{8}[/tex] of the original carbon remains after 17 190 y.

The study of chemicals and bonds is called chemistry.

The correct answer to the question is 1/8years.

What is half-life?

  • Half-life is the time required for a quantity to reduce to half of its initial value.

According to the question, the solution is as follows:-

The half-life of carbon (5730 y) is the time it takes for half the carbon to decay.  After one half-life, half (50 %) of the original amount will remain.  After a second half-life, half of that amount (25 %) will remain, and so on.

The formula used to solve the question is as follows:-

[tex]17190Y*\frac{1}{5730}=3 half \ life[/tex]

The formula used to check the half-life:-

[tex]half \life =\frac{1}{2^n}[/tex]

  • Where n is the half-life.

Thus the half-life 17190 is [tex]\frac{1}{8}[/tex].

Hence, the correct answer is 1/8.

For more information about the half-life, refer to the link:-

https://brainly.com/question/24710827

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