I need help with writing an equation of the line that is perpendicular to the line and passes through (2, 4)?

First find the slope of the original given line:
Slope = 5/3
Points (2,4)
** All perpendicular lines' slope are the negative reciprocal of original slope
- The negative reciprocal of 5/3 is -3/5, therefore -3/5 will be the slope of the perpendicular line
Equations:
Point-slope form: y=4-3/5(x-2)
Slope-intercept: y=-3/5x+5.2
4= -3/5(2)+b
4= -1.2+b
4+1.2=b
5.2=b