contestada

The O'Brien's are building a rectangular deck around the outside of their circular pool.

a.) Find the combined area of the deck and the pool if the deck is (2x + 3) units wide by (5x + 6) units long. (A =LW) Show all work.

b.)If the area of the pool is 3x^2 + 7x + 6, what is the area of just the deck?

Respuesta :

A:

Width of the deck = [tex]2x+3[/tex] units

Length of the deck = [tex]5x+6[/tex] units

So area of rectangular deck = Length * width

= [tex](5x+6)(2x+3)[/tex]

Area = [tex]10x^{2}+15x+12x+18[/tex]

Area= [tex]10x^{2}+27x+18[/tex] units square

As mentioned in part B, the area of the pool is [tex]3x^{2}+7x+6[/tex] so the combined area of the deck and pool is

Area = area of rectangular deck + area of pool

= [tex]13x^{2}+34x+24[/tex] unit square


B:

The area of only the deck is [tex]10x^{2}+27x+18[/tex] unit square