Respuesta :
ANSWER
The correct answer is A.
EXPLANATION
The volume of a cube is given by
[tex]V=l^3[/tex]
First we find the volume of the cube with side length [tex]\frac{3}{4}cm[/tex]
[tex]V_{Cube}=(\frac{3}{4})^3[/tex]
[tex]V_{Cube}=\frac{27}{64} cm^3[/tex]
Next, we find the volume of the cubic block with side length [tex]\frac{3}{8}cm[/tex]
[tex]V_{Block}=(\frac{3}{8})^3[/tex]
[tex]V_{Block}=\frac{27}{512} cm^3[/tex]
We divide the volume of the cube by the volume of the block to get the number of cubic blocks
[tex]Number\: of \: blocks=\frac{\frac{27}{64}} {\frac{27}{512}}[/tex]
[tex]Number\: of \: blocks=\frac{27}{64} \times \frac{512}{27}[/tex]
[tex]Number\: of \: blocks=\frac{1}{1} \times \frac{8}{1}=8[/tex]
Answer:
The correct answer is option A.
8 blocks are needed to fill the box.
Step-by-step explanation:
Given data:
Side length of a block = 3/8 cm
Side length of main block = 3/4 cm
How many blocks are needed to fit in main blocks = ?
Solution:
Volume = length³
Volume of one simple block = (3/8)³ = 27/512 cm³
Volume of one Main block = (3/4)³ = 27/64 cm³
Blocks are needed to fit in main blocks = (27/64) ÷ (27/512) = 8
Answer = 8 blocks
Hence 8 simple small blocks of one side length 3/8 cm will needed to fit in the main block of side length 3/4 cm.