Respuesta :

wegnerkolmp2741o

-3x^4 + 27x^2 + 1200 = 0

factor out -3

-3(x^4 -9x^2 -400)=0

divide by -3

x^4 -9x^2 -400=0

(x^2-25) (x^+16) = 0

x^2-25=0     x^2+16=0

(x-5)(x+5)=0      x^2=-16

x=5   x=-5           x = 4i   x=-4i

Answer:  x=5   x=-5           x = 4i   x=-4i



erolkayacan

Answer:

The answer is 5,-5,4i,-4i.

Step-by-step explanation:

When the equation is divided by -3 it becomes:

[tex]x^4-9*x^2-400=0[/tex]

If we factorize the equation, the equation will become as:

[tex](x+5)*(x-5)*(x^2+16)=0[/tex]

That means the equation has 2 real zeros.

[tex]x=5\\x=-5[/tex]

Also it has 2 complex zeros also. Those are:

[tex]x=-4i\\x=4i[/tex]